IP
= 192.168.5.22
Netmask = 255.255.255.120
Ditanya :
-
Network ID
-
Broadcast ID
-
Range IP
Penyelesaian :
A)
192.168.5.22 = 11000000.10101000.00000101.00010110
255.255.255.120 = 11111111.11111111.11111111.01111000
11000000.10101000.00000101.00011110
192 . 168
. 5 .
30
B)
IP = 11000000.10101000.00000101.00010110
Reverce netmask = 00000000.00000000.00000000.10000111
11000000.10101000.00000101.10010111
192 . 168
. 5 .
151
C range IP = net ID + 1 = 192.168.5.23
C range
IP = net ID - 1 =192.168.5.150
